Time for action – words and letters
To implement the CheckForNewWord()
and its helper methods, we will perform the following steps:
- Add the
PickAWord()
method to the end of theGame1
class, afterDraw()
:private string PickAWord() { switch (rand.Next(15)) { case 0: return "CAT"; case 1: return "DOG"; case 2: return "MILK"; case 3: return "SUN"; case 4: return "SKY"; case 5: return "RAIN"; case 6: return "SNOW"; case 7: return "FAR"; case 8: return "NEAR"; case 9: return "FRIEND"; case 10: return "GAME"; case 11: return "XNA"; case 12: return "PLAY"; case 13: return "RUN"; case 14: return "FUN"; } return "BUG"; }
- Add the
FillLetters()
method to theGame1
class, afterPickAWord()
:private void FillLetters(string word) { Rectangle safeArea = new Rectangle( this.Window.ClientBounds.Width / 2 - playerSquare.Width, this.Window.ClientBounds.Height / 2 - playerSquare.Height, playerSquare.Width * 2, playerSquare.Height * 2); string alphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"; List<Vector2> locations = new List<Vector2>(); for (int x=25;x < this.Window.ClientBounds.Width - 50;x += 50) { for (int y=25;y < this.Window.ClientBounds.Height - 50;y += 50) { Rectangle locationRect = new Rectangle( x, y, (int)letterFont.MeasureString("W").X, (int)letterFont.MeasureString("W").Y); if (!safeArea.Intersects(locationRect)) { locations.Add(new Vector2(x, y)); } } } letters.Clear(); for (int x = 0; x < 20; x++) { GameLetter thisLetter = new GameLetter(); if (x < word.Length) thisLetter.Letter = word.Substring(x, 1); else thisLetter.Letter = alphabet.Substring( rand.Next(0,26),1); int location = rand.Next(0,locations.Count); thisLetter.Position = locations[location]; thisLetter.WasHit = false; locations.RemoveAt(location); letters.Add(thisLetter); } }
- Add the
CheckForNewWord()
method to the end of theGame1
class, afterFillLetters()
:private void CheckForNewWord() { if (currentLetterIndex >= currentWord.Length) { playerPosition = new Vector2( this.Window.ClientBounds.Width / 2, this.Window.ClientBounds.Height / 2); currentWord = PickAWord(); currentLetterIndex = 0; FillLetters(currentWord); } }
What just happened?
In step 1, we generate a random number using the Next()
method of the Random
class. Given an integer value, Next()
will return an integer between zero and that number minus one, meaning we will have a return value from zero to fourteen. Using a select
statement, we return the randomly determined word. Note that we should never hit the last return statement in the function, so if we are ever asked to spell the word BUG
, we know something is wrong.
The FillLetters()
method is used to populate the letters
list with letters and their locations on the screen. We could simply generate random locations for each letter, but then this would leave us with the potential for letters overlapping each other, requiring a check as each letter is generated to ensure this does not happen.
Instead, we will generate a list of potential letter positions by building the locations
list. This list will contain each of the possible places on the screen where we will put a letter by spacing through a grid and adding entries every 25 pixels in the x and y directions. The exception is that we define an area in the center of the screen where the player will start and we will not place letters. This allows the player to start each round without being in contact with any of the game letters.
Once we have our list of locations, we clear the letters
list and generate 20 letters. We start with the letters required to spell the target word, pulling letters from the currentWord
string until we reach the end. After that, the letters will come from the alphabet
string randomly. Each letter is assigned one of the locations from the locations
list, and that location is then removed from the list so we will not have two letters on top of each other.
Lastly, the CheckForNewWord()
method checks to see if currentLetterIndex
is larger than the length of currentWord
. If it is, the player's position is reset to the center of the screen and a new word is generated using PickAWord()
. currentLetterIndex
is reset, and the letters
list is rebuilt using the FillLetters()
method.